How do you graph the inequality #y<x-3#?
1 Answer
Jun 15, 2018
See a solution process below:
Explanation:
First, solve for two points as an equation instead of an inequality to find the boundary line for the inequality.
For:
For:
We can now graph the two points on the coordinate plane and draw a line through the points to mark the boundary of the inequality.
graph{(x^2+(y+3)^2-0.035)((x-4)^2+(y-1)^2-0.035)(y-x+3)=0 [-10, 10, -5, 5]}
Now, we can shade the right side of the line.
We also need to change the boundary line to a dashed line because the inequality operator does not contain an "or equal to" clause.
graph{(y-x+3) < 0 [-10, 10, -5, 5]}