# How do you graph the lines using slope-intercept form #h(x) = -x+7#?

##### 1 Answer

Feb 1, 2016

graph{-x+7 [-10, 10, -5, 5]}

#### Explanation:

**1) Use the equation and what we know about slope-intercept form to find the slope and y-intercept.**

The slope-intercept form equation is:

Therefore, the ** slope (** is

**is**

*y-intercept (*#b# )**2) Find the *x-intercept***

Set the equation equal to

So the x-intercept is (7,0)

**3) Use what we know to create a graph**

- Because of the
, we know the graph crosses the y-axis at*y-intercept*#(0,7)# . - Because of the
, we know that the graph crosses the x-axis at*x-intercept*#(7,0)# - Because the
is*slope**negative*, we know that the graph is going down. - Because the
is rise over run we can use up 1 over 1 to graph a few points and create a line*slope*

OR

Create a table or list of coordinates by:

#x-1# ,#y+1# if using the. So:*x-intercept*#(7,0), (6,1), (5,2),# etc.

or

#x+1, y-1# if using the. So:*y-intercept*#(0,7), (1,6), (2,5)# , etc.