How do you graph the parabola f(x)=x ^2 + 3x-10f(x)=x2+3x−10 using vertex, intercepts and additional points?
2 Answers
After calculating the vertex and intercepts and plotting them, calculate additional points,
Explanation:
To find the vertex, we use the formula
Standard form is
In our case:
This means the
Plugging the
Our vertex is therefore
Now, we can calculate the
The
So, our
The
So, our
Now, we have four relevant points that we can plot. These are:
- The vertex,
(-3/2,-49/4)(−32,−494) - The
xx -intercepts,(-5,0)(−5,0) and(2,0)(2,0) - And the
yy -intercept,(0,-10)(0,−10)
After plotting these, we likely wish to plot some additional points in between to more accurately graph it. We would choose
These would be points within our range of crucial coordinates, so anywhere between our lowest
You may also plot more points outside of this range to give a more complete picture.
ME (Harold Walden)
Explanation:
I have handwritten my explanation, I hope it is legible :)Again, the source is me :)
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