How do you graph the parabola #y=-2x^2# using vertex, intercepts and additional points?

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Answer 1 · 2017-11-01T06:42:16

Refer the explanation section.

Given -

#y=-2x^2#

It has no constant term. Hence its origin is #(0, 0)#

Since the coefficient of #x^2# is negative, the parabola opens down.

Choose a few points on either side of #x=0#. Calculate the corresponding #y# values.

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Plot the points on a graph sheet.
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You get the graph.