Question

How do you graph the parabola `y=3x^2` using vertex, intercepts and additional points?

Answer 1

Take `y=ax^2+bx+c` as example.

Explanation:

Where `bandc` give information.
Since both `b=0andc=0` the vertex must be at `(0,0)`, and this is also the only `x` intercept.
For additional points you can make up a table with `x` values and the calculated `y` values.
graph{3x^2 [-14.47, 17.56, -4.29, 11.72]}