Question

How do you graph the parabola `y=4x^2`?

Answer 1

Explanation:

Put the values -3, -2, -1, 0, 1, 2, 3 into the equation instead of x.
Square the number and then multiply the answer by 4. This will produce corresponding y values.

The quadratic is positive so the parabola is `uu` shaped.

`[-b]/[2a]=0/8=0` this is the x coordinate of the vertex

(which is a minimum). The graph is symmetrical about the y axis.
graph{4x^2 [-10, 10, -5, 5]}