How do you graph the parabola #y = 4x^2 + 8x -22# using vertex, intercepts and additional points?

1 Answer
Jan 19, 2018

UNDERSTAND THE EXPLANATION

Explanation:

#y=4x^2+8x-22#

Taking out 4 as a common factor as 'a' is always a factor to be taken out

#y=4(x^2+2x-11/2)#

use completing the square method

#y=4(x^2+2x+1-11/2-1)#

convert the equation in the form #y=a(x-h)^2+k#

#y=4(x+1)^2-13/2#

I hope now can get vertex, x, and y-intercept AND axis of symmetry
if not then mention me in the comment for further help