Question

How do you graph the parabola `y = 4x^2 + 8x -22` using vertex, intercepts and additional points?

Answer 1

UNDERSTAND THE EXPLANATION

Explanation:

`y=4x^2+8x-22`

Taking out 4 as a common factor as 'a' is always a factor to be taken out

`y=4(x^2+2x-11/2)`

use completing the square method

`y=4(x^2+2x+1-11/2-1)`

convert the equation in the form `y=a(x-h)^2+k`

`y=4(x+1)^2-13/2`

I hope now can get vertex, x, and y-intercept AND axis of symmetry
if not then mention me in the comment for further help