Question

How do you graph the parabola `y=(x-7)(x-3)` using vertex, intercepts and additional points?

Answer 1

graph{(x-7)(x-3) [-10, 10, -5, 5]}

`x_0=7 or x_0=3`
Vertex: `(5,-4)`

Explanation:

A zero function is in x=7 and x=3.
Vertex of parabola is in `x=(7+3)/2=5`
We can calculate the value of the function (y of vertex): `f(5)=(x-7)(x-3)=(5-7)(5-3)=(-2)*(2)=-4`