# How do you graph the system of linear inequalities #5x-3y<=4# and #x+y<8# and #y>3#?

##### 1 Answer

Jun 8, 2018

f2(x,y) = x + y - 8 < 0

f3(y) = y - 8 > 0

This system of linear inequalities in 2 variables must be solved by graphing.

First, graph the 2 lines f1(x,y) and f2(x,y) by axis intersects.

f1(x,y) = 5x - 3y - 4 = 0

x = 0 -->

y = 0 -->

f2(x,y) = x + y - 8 = 0

x = 0 --> y = 8

y = 0 --> x = 8

The solution set of

The solution of f2(x,y) < 0 is the area below the line f2(x,y)

The solution set of f3(x,y) > 3 is the area above the line y = 3.

The solution set of the system is the commonly shared area of the 3 above solutions sets.