How do you graph the system of linear inequalities #y> -5#, #x>3# and #2x+y<13#?

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Answer 1 · 2018-02-28T09:40:46

The dark blue triangle is the solution

You must represent each graph in the euclidean plane

#y>-5# are all points of plane having second coordinate bigger than -5

#x>3# are all the points of plane having first coordinate bigger than 3

Finally, #2x+y<13# are the points of plane below the line represented by #y=13-2x#

The interception points can be calculated by

#y=13-2x#
#y=-5#

So, #-5=13-2x# hence #x=-9# Intercep. Point #(-9, -5)#

The other two points can be found in the same way

The intersection of three areas is the searched solution

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