How do you graph two complete cycles of #y=1/2sint#?

1 Answer
Jul 31, 2018

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Please read the explanation.

Explanation:

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Create a data table for the Parent function #color(red)(y=f(t)=sin(t)# as shown below:

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Graph the Parent function as shown below:

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Next, graph the function: #color(red)(y=f(t)=(1/2)*sin(t)#

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Now, we understand the behavior of the graph

#color(red)(y=f(t)=(1/2)*sin(t)#

by comparing it to the parent graph.

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The question reads draw two complete cycles.

The Period of a trigonometric function is the horizontal length of one complete cycle.

The Sine curve, #color(red)(y=sin(t)#, has a Period of #color(blue)(2 pi#.

The Sine curve, #color(red)(y=(1/2)*sin(t)#, has also a Period of #color(blue)(2 pi#.

We need to restrict or place a constraint using an appropriate condition as shown below:

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Again, we can compare the restricted graphs of both the parent function and the given function for easy comprehension.

I hope it helps.