# How do you graph two or more functions on the same graph with the graphing utility on Socratic.org?

##### 5 Answers

#### Answer:

Write each equation as an expression = 0. Then set the product of the expressions equal to

#### Explanation:

To graph

Graph: (y-x^2)(y-x-3)=0

graph{(y-x^2)(y-x-3)=0 [-7.17, 15.33, -2.43, 8.82]}

And if you're patient enough to type this: (you can do one copy and paste) **See Edit Below**

(y-x^2)(y-x-3)(sqrt(13/4-(x-1/2)^2))/(sqrt(13/4-(x-1/2)^2) ) <= 0

then you can get just the region bounded by the two:

graph{(y-x^2)(y-x-3)(sqrt(13/4-(x-1/2)^2))/(sqrt(13/4-(x-1/2)^2) ) <= 0 [-4.624, 7.864, -0.51, 5.72]}

**Edit**

It looks like the grapher works by solving

So we can restrict the domain of a function

For example, To restrict the domain of

(y-x^2)sqrt(-(x+1)(x-2))=0

graph{(y-x^2)sqrt(-(x+1)(x-2))=0 [-5.404, 8.645, -0.9, 6.11]}

To restrict to

For example, (y-x^3)sqrt(x+1)=0 restricts the cube to

graph{(y-x^3)sqrt(x+1)=0 [-7.33, 10.45, -2.37, 6.5]}

If you wanted to graph the lines:

The best thing I've seen to do is to manipulate them both so that they're both equal to

And then put the equations into the graphing tool as a product of the two equations which equals

Without hashtags:

(y-3x-2)(y+1/2x+5)=0

graph{(y-3x-2)(y+1/2x+5)=0 [-15.55, 12.93, -8.66, 5.58]}

This can be done with more than lines, too:

graph{((x-500)^2+(y-500)^2-500^2)((x-250)^2+(y-750)^2-100^2)((x-750)^2+(y-750)^2-100^2)((y-500)^2/150^2+(x-500)^2/50^2-1)((x-500)^2/200^2+(y-200)^2/75^2-1)=0 [-580, 1644, -100, 1076]}

What went into the grapher:

((x-500)^2+(y-500)^2-500^2)((x-250)^2+(y-750)^2-100^2)((x-750)^2+(y-750)^2-100^2)((y-500)^2/150^2+(x-500)^2/50^2-1)((x-500)^2/200^2+(y-200)^2/75^2-1)=0

#### Answer:

Express as

#### Explanation:

If you have functions

#(y-f(x))(y-g(x)) = 0#

That usually works.

For example,

graph{(y-x^2)(y-sin x) = 0 [-10, 10, -5, 5]}

#### Answer:

As seen below...

#### Explanation:

There are few ways of doing this, but one way is by using this idea...

Defining your first function...

Your second function...

As this gives you solutions:

graph{(y - e^x )(y + x^2) = 0 [-5.018, 4.98, -2.04, 2.96]}

This can be obtaine by:

Another method is via using 'desmos' a graphing software...

This is another method that we can use...

This is a good website for also plotting coodinates, if needed...

This is also a great website for solving and plotting inequalities...

#### Answer:

See below

#### Explanation:

Notice that these 3 commands generate the same graph

graph

If you don't set the display range, it will be set to default

[-10, 10, -5, 5]

Now the magic starts: we multiply 2 expressions that are equal to 0.

For example a parabola and a circle:

graph##{(y-x^2)(x^2+y^2-1)=0}

graph{(y-x^2)(x^2+y^2-1)=0}

You can shift and strech at will:

graph

graph{(y-2-(x+3)^2)(((x-4)/2)^2+(y+1)^2-1)=0}

Simplifying these expressions mathematically doesn't affect graph.

For example if we want to draw lines

graph##{y^2-x^2=0}

graph{y^2-x^2=0}

Also we can restrict te domain to basically any subset of XY plane we can imagine. For example a circle with radius 3.

graph##{(y^2-x^2)(y^2-4x^2)(4y^2-x^2)sqrt(9-x^2-y^2)=0}

graph{(y^2-x^2)(y^2-4x^2)(4y^2-x^2)sqrt(9-x^2-y^2)=0}