# How do you graph using slope and intercept of - 5x + y =0?

Dec 21, 2015

You have to move some things around in the equation to put it into slope-intercept form, then you can graph it.

#### Explanation:

$- 5 x + y = 0$

Slope intercept form is: $y = m x + b$

First, you need to get the $y$ alone on the left side of the equation.
$- 5 x + y = 0$
$- 5 x + y + 5 x = 0 + 5 x$
$y = 0 + 5 x$

Now, the equation is almost correct and ready to be graphed, but for it to be technically correct, the place of the $0$ and the $5 x$ need to be switched.
$y = 5 x + 0$

So, you know that the y-intercept is $0$, which means that it is at the point $\left(0 , 0\right)$
Plot a point at $\left(0 , 0\right)$

Then, since you have a slope of $5$, that means you have a rise, or change in the $y$ value, of $+ 5$, and a run, or change in the $x$ value, of $+ 1$

Starting at point $\left(0 , 0\right)$, plot at point five up, and one to the right. So, that point would be at $\left(1 , 5\right)$. Then, from $\left(1 , 5\right)$, go up five, and to the right one, so you'll be at point $\left(2 , 10\right)$. Then, draw a line through your points.