Question

How do you graph using slope and intercept of `6x - 3y = -12`?

Answer 1

`6x-3y=-12` has a slope of `2` and a y-intercept of `4`
Starting at the y-intercept `(0,4)` plot points by repetitively going 1 step right and 2 steps up.

Explanation:

The y-intercept is the value of `y` when `x=0`
For `6x-3y=-12` when `x=0`
`color(white)("XXX")6(0)-3y=-12 rArr y=4`
So the y-intercept is at `(0,4)`

The slope for an equation in the form
`color(white)("XXX")Ax+By=C`
is `m=-A/B`
So the slope of
`color(white)("XXX")6x-3y=-12`
is `m= -6/(-3) = 2`

A slope of `2` means that for every steep in the positive `x` direction the value of `y` must increase by `2`

graph{(6x-3y+12)(x^2+(y-4)^2-0.01)((x-1)^2+(y-6)^2-0.01)((x-2)^2+(y-8)^2-0.01)=0 [-2.505, 17.495, -0.6, 9.4]}