# How do you graph using slope and intercept of 8x + 7y = -16?

Slope $m = - \frac{8}{7}$ and y-intercept $b = - \frac{16}{7} \cong - 2.285$

#### Explanation:

Once the slope and the y-intercept has been computed, use a graphing paper. Then, you can now locate the intercept
at $\left(0 , b\right) = \left(0 , - \frac{16}{7}\right) = \left(0 , - 2.285\right)$

when you already located this point, count 7 units to the left then count 8 units up. This means, when you count 7 units to the left, you temporarily stop at (-7, -2.285). Afterwards, you will count 8 units upward to find (-7, 5.715).

At this point, you now have two points $\left(0 , - 2.285\right)$ and
$\left(- 7 , 5.715\right)$.

Connecting these two points will be the graph of the line $8 x + 7 y = - 16$

graph{8x+7y=-16[-30,30,-15,15]}

God bless... I hope my explanation is useful...