How do you graph using slope and intercept of #8x + 7y = -16#?
Once the slope and the y-intercept has been computed, use a graphing paper. Then, you can now locate the intercept
when you already located this point, count 7 units to the left then count 8 units up. This means, when you count 7 units to the left, you temporarily stop at (-7, -2.285). Afterwards, you will count 8 units upward to find (-7, 5.715).
At this point, you now have two points
Connecting these two points will be the graph of the line
God bless... I hope my explanation is useful...