How do you graph using slope and intercept of -x+5y=-5?

Nov 10, 2015

The slope is $\frac{1}{5}$.
The y-intercept is $- 1$.
The x-intercept is $5$.

Explanation:

$- x + 5 y = - 5$ is a linear equation in standard form. Convert it to the slope intercept form by solving for $y$.

$- x + 5 y = - 5$

Add $x$ to both sides.

$5 y = x - 5$

Divide both sides by $5$.

$y = \frac{x}{5} - \frac{5}{5} =$

$y = \frac{1}{5} x - 1$

$y = \frac{1}{5} x - 1$ is the slope intercept form of a linear equation, $y = m x + b$, where $m$ is the slope, $\frac{1}{5}$ and $b$ is the y-intercept, $- 1$.

The y-intercept is the value of $y$ when $x = 0$. The point of the y-intercept is $\left(0 , - 1\right)$.

The x-intercept is the value of $x$ when $y = 0$.

$0 = \frac{1}{5} x - 1$

Add $1$ to both sides.

$1 = \frac{1}{5} x$

Multiply both sides times $5$.

$1 \cdot 5 = \frac{1}{\cancel{5}} x \cdot \cancel{5} =$

$5 = x$

Switch sides.

$x = 5$

The x-intercept is $5$. The point of the x-intercept is $\left(5 , 0\right)$.

Plot the two points and draw a straight line through the points.

graph{y=1/5x-1 [-16.02, 16, -8.01, 8.01]}