# How do you graph using the intercepts for #x+2y=5#?

##### 2 Answers

See below

#### Explanation:

To find the intercepts, substitute in

Substitute

Therefore, the y-intercept is

Substitute

Therefore, the x-intercept is

If you do not already know so, the x-intercept is where the line touches or crosses through the x-axis and the y-intercept is where the line touches or crosses through the y-axis.

Now that you know the intercepts, simply indicate on the graph the points

graph{x+2y=5 [-7.54, 12.46, -3.48, 6.52]}

graph{(x^2+(y-5/2)^2-0.01)((x-5)^2+y^2-0.01)(x+2y-5)=0 [-2.59, 7.273, -0.85, 4.08]}

#### Explanation:

Given the linear equation

#{:

(x"-intercept=value of "x" when "y=0," | ",y=0rArrx=5," | ","point: "(5,0)),

(y"-intercept=value of "y" when "x=0," | ",x=0rArry=5/2," | ","point: "(0,5/2))

Plotting each of the two points on the Cartesian plane and drawing a line through them gives the graph shown in the Answer.

:}#