Question

How do you graph using the intercepts for `x+2y=5`?

Answer 1

See below

Explanation:

To find the intercepts, substitute in `x=0` to find the y-intercept and `y=0` to find the x-intercept, so:

Substitute `x=0` into `x+2y=5`
`0+2y=5`
`2y=5`
`y=5/2`
Therefore, the y-intercept is `y=5/2`, also written as `y=2.5`

Substitute `y=0` into `x+2y=5`
`x+2(0)=5`
`x=5`
Therefore, the x-intercept is `x=5`

If you do not already know so, the x-intercept is where the line touches or crosses through the x-axis and the y-intercept is where the line touches or crosses through the y-axis.

Now that you know the intercepts, simply indicate on the graph the points `(5, 0)`(the x-intercept) and `(0, 2.5)` (the y-intercept) and draw a line connecting the dots, so the graph would be:

graph{x+2y=5 [-7.54, 12.46, -3.48, 6.52]}

Answer 2

`x+2y=5`
graph{(x^2+(y-5/2)^2-0.01)((x-5)^2+y^2-0.01)(x+2y-5)=0 [-2.59, 7.273, -0.85, 4.08]}

Explanation:

Given the linear equation `x+2y=5`

#{:
(x"-intercept=value of "x" when "y=0," | ",y=0rArrx=5," | ","point: "(5,0)),
(y"-intercept=value of "y" when "x=0," | ",x=0rArry=5/2," | ","point: "(0,5/2))

Plotting each of the two points on the Cartesian plane and drawing a line through them gives the graph shown in the Answer.
:}#