How do you graph using the intercepts for # x-2y=8#?

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Answer 1 · 2018-03-18T20:35:26

#y = 1/2x - 4#

Recall the formula for a linear equation:

#y = mx + b#

So

#x - 2y = 8#

#-2y = 8 - x#

#y = 1/2x - 4#

Using the #y#-intercept of #-4#, plot this on your graph.

graph{y = 1/2x -4 [-10, 10, -5, 5]}

#1/2 = "Rise"/"Run"#

Continue to plot points on the graph, moving up one value once, and right a value twice.

Hope this helps. :)