How do you graph using x and y intercept of #3x-4y+2=0#?

1 Answer
Mar 14, 2017

Answer:

Please see below.

Explanation:

We can find #x#-intercept by putting #y=0# in the given equation #3x-4y+2=0# and #y#-intercept by putting #y=0# in the equation.

Hence #x#-intercept is given by #3x-4xx0+2=0# i.e. #x=-2/3# at #(-2/3,0)#

and #y#-intercept is given by #3xx0-4y+2=0# i.e. #y=1/2# at #(0,1/2)#

The graph will be obtained by joining #(-2/3,0)# and #(0,1/2)# and appears as given below.

graph{3x-4y+2=0 [-3.177, 1.823, -1.28, 1.22]}