# How do you graph # (x - 2)^2 + 3(y - 2)^2 = 25#?

##### 1 Answer

Jul 22, 2017

Please see below.

#### Explanation:

or

an ellipse, whose center is

End points of major axis are

End points of minor axis are

It appears as follows:

graph{((x-2)^2+3(y-2)^2-25)((x+3)^2+(y-2)^2-0.02)((x-7)^2+(y-2)^2-0.02)((x-2)^2+(y-2+5/sqrt3)^2-0.02)((x-2)^2+(y-2-5/sqrt3)^2-0.02)=0 [-8.5, 11.5, -3.2, 6.8]}