How do you graph (x + 2)^2 + (y + 1)^2 = 32?

A circle centred at the point $\left(a , b\right)$ and having radius $r$, has equation
${\left(x - a\right)}^{2} + {\left(y - b\right)}^{2} = {r}^{2}$
So in this case, ${\left(x + 2\right)}^{2} + {\left(y + 1\right)}^{2} = {\left(\sqrt{32}\right)}^{2}$ is a circle centred at the point $\left(- 2 , - 1\right)$ and having radius $\sqrt{32}$.