Question

How do you graph `(x + 2)^2 + (y + 1)^2 = 32`?

Answer 1

A circle centred at the point `(a,b)` and having radius `r`, has equation
`(x-a)^2+(y-b)^2=r^2`

So in this case, `(x+2)^2+(y+1)^2=(sqrt32)^2` is a circle centred at the point `(-2,-1)` and having radius `sqrt32`.