Question

How do you graph `x=y^2-2y`?

Answer 1

See below:

Explanation:

Let's first notice that the graph is going to have a parabolic shape. Since the parabolic portion of the equation is in `y` and not in `x`, the graph itself is going to be "sideways". We can chart out a few values to see what it's going to look like. It might be easier to look at `y` values first and then find the resulting `x`:

`((y,x),(0,0),(1,-1),(-1,3),(2,0),(-2,8),(3,3))`

Let's plot those, then connect the line:

graph{((x-0)^2+(y-0)^2-.1)((x+1)^2+(y-1)^2-.1)((x-3)^2+(y+1)^2-.1)((x-0)^2+(y-2)^2-.1)((x-8)^2+(y+2)^2-.1)((x-3)^2+(y-3)^2-.1)(y^2-2y-x)=0}