# How do you graph x+y> -5?

Aug 22, 2017

See a solution process below:

#### Explanation:

First, solve for two points as an equation instead of a inequality to find the boundary line for the inequality.

For $x = 0$

$0 + y = - 5$

$y = - 5$ or $\left(0 , - 5\right)$

For $y = 0$

$x + 0 = - 5$

$x = - 5$ or $\left(- 5 , 0\right)$

We can now graph the two points on the coordinate plane and draw a line through the points to mark the boundary of the inequality.

graph{(x+y+5)(x^2+(y+5)^2-0.3)((x+5)^2+y^2-0.3)=0 [-30, 30, -15, 15]}

To complete the chart of the inequality we need to make the boundary line a dashed line because there is no "or equal to" clause in the inequality. And we need to shade the right side of the line:

graph{(x+y+5)>0 [-20, 20, -10, 10]}