Question

How do you graph `x+y> -5`?

Answer 1

See a solution process below:

Explanation:

First, solve for two points as an equation instead of a inequality to find the boundary line for the inequality.

For `x = 0`

`0 + y = -5`

`y = -5` or `(0, -5)`

For `y = 0`

`x + 0 = -5`

`x = -5` or `(-5, 0)`

We can now graph the two points on the coordinate plane and draw a line through the points to mark the boundary of the inequality.

graph{(x+y+5)(x^2+(y+5)^2-0.3)((x+5)^2+y^2-0.3)=0 [-30, 30, -15, 15]}

To complete the chart of the inequality we need to make the boundary line a dashed line because there is no "or equal to" clause in the inequality. And we need to shade the right side of the line:

graph{(x+y+5)>0 [-20, 20, -10, 10]}