# How do you graph x+y=5 using intercepts?

Jun 6, 2017

#### Answer:

Plot points and connect the dots.

#### Explanation:

First, plot the $x$ intercept. You get this by setting $y = 0$.

$x + 0 = 5$

$x = 5$

This gives the point $\left(5 , 0\right)$, plotted here:

graph{((x-5)^2+(y-0)^2 - 1/100)=0 [-1.904, 15.874, -3.68, 5.21]}

Next, plot the $y$ intercept. You get this by setting $x = 0$.

$0 + y = 5$

$y = 5$

This gives the point $\left(0 , 5\right)$, plotted here:

graph{((x-5)^2+(y-0)^2 - 1/100)((x-0)^2+(y-5)^2 - 1/100)=0 [-1.904, 15.874, -3.68, 5.51]}

Finally, draw a line connecting the two points on the graph. The solution looks like this:

graph{((x-5)^2+(y-0)^2 - 1/100)((x-0)^2+(y-5)^2 - 1/100)(x+y-5)=0 [-1.904, 15.874, -3.68, 5.51]}