How do you graph #x+y=8# using intercepts?

1 Answer
Jan 15, 2017

Answer:

Please see below.

Explanation:

There are two ways of doing it.

One #-># The intercept form of the equation is #x/a+y/b=1#, where #a# and #b# are the intercepts formed by the line on #x#-axis and #y#-axis.

As the equation is #x+y=8#, dividing each term by #8#, we get

#x/8+y/8=1#

and hence, intercepts formed by the line on #x#-axis is #8# and on #y#-axis too it is #8#. Hence mark the intercepts #8# on each axis and join them to draw the graph of #x+y=8#.

Two #-># Just put #x=0# to get #y#-intercept, it comes out as #8#, and put #y=0# to get #x#-intercept, which too comes out as #8#.

Now as above mark the two intercepts and join to form line.
graph{((x-8)^2+y^2-0.025)((y-8)^2+x^2-0.025)(x+y-8)=0 [-7.79, 12.21, -1.32, 8.68]}