Question

How do you graph `x+y=8` using intercepts?

Answer 1

Please see below.

Explanation:

There are two ways of doing it.

One `->` The intercept form of the equation is `x/a+y/b=1`, where `a` and `b` are the intercepts formed by the line on `x`-axis and `y`-axis.

As the equation is `x+y=8`, dividing each term by `8`, we get

`x/8+y/8=1`

and hence, intercepts formed by the line on `x`-axis is `8` and on `y`-axis too it is `8`. Hence mark the intercepts `8` on each axis and join them to draw the graph of `x+y=8`.

Two `->` Just put `x=0` to get `y`-intercept, it comes out as `8`, and put `y=0` to get `x`-intercept, which too comes out as `8`.

Now as above mark the two intercepts and join to form line.
graph{((x-8)^2+y^2-0.025)((y-8)^2+x^2-0.025)(x+y-8)=0 [-7.79, 12.21, -1.32, 8.68]}