How do you graph # y=1+2cos(1/2x+pi/2)#?

1 Answer
Jun 10, 2018

Answer:

graph{y=1+2cos(.5x + pi/2) [-10, 10, -5, 5]}

Explanation:

Just like graphing a regular function find the vertical stretch factor, horizontal stretch factor, horizontal shift, and vertical shift:
it is shifted up 1 and to the left #pi/2#
it has a vertical stretch actor of 2
it has a horizontal stretch factor of 2
except this is on a cosin function so it looks like this.
graph{y=1+2cos(.5x + pi/2) [-10, 10, -5, 5]}