# How do you graph y=1/3x-4 using intercepts?

Apr 18, 2017

The $y$ intercept is when $x = 0$

$y = \frac{1}{3} x - 4$ $\implies$ $y = \frac{1}{3} \left(0\right) - 4$ $\implies$ $y = - 4$

When $x = 0$, $y$ is $- 4$, so you have the point $\left(0 , - 4\right)$

The $x$ intercept is when $y = 0$

$y = \frac{1}{3} x - 4$ $\implies$ $0 = \frac{1}{3} x - 4$

$\frac{1}{3} x = 4$ $\implies$ $\cancel{3 \cdot \frac{1}{3}} x = 4 \cdot 3$

$x = 12$

When $y = 0$, $x$ is $12$, so you have the point $\left(12 , 0\right)$

You have these two points, plot them in the graph and connect them by a straight line extended beyond them. By this you have done the graphing by using intercepts.