How do you graph #y=1/4x+.5# and #y=-2x-4# on the same axis?

1 Answer
Jan 28, 2018

See below.

Explanation:

The equation of a straight line in slope/intercept form is:
#y=mx+c#: where slope #=m and y-#intercept #=c#

In this example:

#y = 1/4x+0.5# [A]
#y = -2x-4 # [B]

Both [A] and [B] are equations of straight lines.

[A] has a slope of #1/4# and a #y-#intercept of #0.5#

[B] has a slope of #-2# and a #y-#intercept of #-4#

We can graph [A] and [B] on the same #xy-#plane as below.

graph{(x/4+0.5-y)(-2x-4-y)=0 [-16.02, 16.01, -8.01, 8]}

NB: From the graph we can see the solution of the system of linear equatons [A] and [B] is #x=-2, y=0#