How do you graph #y = 1 + |x-1|#?
The two vertical lines mean that for this equation the content is always positive and is of generic shape
You produce a table setting x against y.
Technically you only need 3 points and these are
The lowest value the equation can achieve and any other two pints so that you can form the V shape
Table to demonstrate what happens to the numbers:
At (1, 1) make a right angle by drawing the straight lines
The lines are half lines above the common point (1, 1 )..