# How do you graph y=2(1/3)^(x+1)-3?

Feb 6, 2017

Plug and plot

#### Explanation:

I would just try values.

if $x = - 2$ then $y = 3$

if $x = - 1$ then $y = - 1$

if $x = 0$ then $y = - \frac{7}{3}$

if $x = 1$ then $y = - \frac{25}{9}$

Then graph, connecting the points
graph{2(1/3)^(x+1)-3 [-10, 10, -5, 5]}