Question

How do you graph `y = (-2/3)x + 4` by plotting points?

Answer 1

Now draw a line passing through the points:(0, 4) and (6, 0).

Explanation:

`y=(-2/3)x+4` => equation of a line in slope-intercept form
To draw a straight line all you need is two points on the line, then you can draw a line passing through the points.

Give some values to x then solve for y:
`x = 0`
`y=(-2/3)*0+4`
`y=4` => so point (0, 4) is on the line
`x = 6`
`y=(-2/3)*6+4`
`y=-4+4`
`y=0` => so point (6, 0) is on the line
Now draw a line passing through the points:(0, 4) and (6, 0).