# How do you graph y=-2+8x?

Apr 25, 2017

$x$ intercept is $\left(\frac{1}{4} , 0\right)$

$y$ intercept is $\left(0 , - 2\right)$

slope is $8$

#### Explanation:

We need a few pieces of information to be able to graph a function. We need the $x$ and $y$ intercepts and the slope.

We can use slope-intercept form to help us find two of these components. Slope-line form is $y = m x + b$, where $m$ is slope and $b$ is the $y$ intercept.

In our case, $m$ is $8$, so our slope is $8$, and our $y$ intercept is $- 2$.

So, we have our slope and $y$ intercept, but we still need our $x$ intercept. To find that, we set $y$ to $0$ and solve for $x$:

$0 = - 2 + 8 x$

add $2$ to both sides

$2 = 8 x$

divide by $8$

$\frac{1}{4} = x$

So, our $x$ intercept is $\left(\frac{1}{4} , 0\right)$, our $y$ intercept is $\left(0 , - 2\right)$, and our slope is $8$, or up $8$, over $1$

The final graph should look like this:
graph{y=-2+8x}