How do you graph #y =2 abs(x-4)+ 1#?

1 Answer
Jul 22, 2015

Answer:

Graph the domain for #(x-4) <= 0# and then the domain for #(x-4)>= 0#

Explanation:

Note that the two components are both linear, so only 2 points are required for each.

For #(x-4) <=0#
#color(white)("XXXX")#if #x=4 rarr y = 2abs(0) + 1 = 1#
#color(white)("XXXX")#if #x = 0 rarr y = 2(abs-4) + 1 = 9#

For #(x-4) >= 0#
#color(white)("XXXX")#if #x=4 rarr y = 2abs(0) + 1 = 1#
#color(white)("XXXX")#if #x= 8 rarr y = 2abs(4)+1 = 9#

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