# How do you graph y< 2^(x-4)?

Jan 6, 2017

See graph and explanation.

#### Explanation:

$y < {2}^{x} {2}^{- 4} = \frac{1}{16} \left({2}^{x}\right)$

The region { ( x, y ) } for the inequality is below the boundary curve

$y = \frac{1}{16} \left({2}^{x}\right) > 0. y \to 0$ as $x \to - \infty \mathmr{and} \to \infty$, as x to oo#,

with y-intercept $\left(x = 0\right) = \frac{1}{16}$.

As $y ' = \ln 2 \left({2}^{x}\right) > 0 , y \uparrow$ as x $\uparrow .$

graph{y-2^x/16<0 [-8.514, 8.5, -4.296, 4.207]}