Question

How do you graph `y< 2^(x-4)`?

Answer 1

See graph and explanation.

Explanation:

`y<2^x 2^(-4)=1/16(2^x)`

The region { ( x, y ) } for the inequality is below the boundary curve

`y = 1/16 (2^x) > 0. y to 0` as `x to -oo and to oo`, as x to oo#,

with y-intercept `( x = 0 ) = 1/16`.

As `y'= ln 2 (2^x) > 0, y uarr` as x `uarr.`

graph{y-2^x/16<0 [-8.514, 8.5, -4.296, 4.207]}