How do you graph #y=2sqrt(x+2)# and compare it to the parent graph?
1 Answer
Sep 9, 2017
Determine and apply the transformations to the base function.
Explanation:
There are two transformations applied to this function.
Compared to the base function:
graph{sqrtx [-10, 10, -5, 5]}
These transformations are:
- Vertical stretch by a factor of
#2# . This is caused by the#a# -value. - Horizontal translation
#2# units to the left. Due to horizontal format of doing the opposite (essentially) of what would normally be done, the function moves.
As a result, we get a function that looks like this:
graph{2sqrt(x+2) [-10, 10, -5, 5]}
If we were to compare this to the parent graph, the transformed function is stretched and "starts"
Hope this helps :)