# How do you graph y=2x^2+6?

Sep 4, 2015

Refer the explanation section

#### Explanation:

Its vertex is at
$x = \frac{- b}{2 a}$

'b' term is not there in the function.
Then we shall write the function like this
$a x 2 + b x + c$ - This is the general form of the function.
The our function shall be writter as -
$2 {x}^{2} + 0 x + 6$

Now find the vertex -
$x = \frac{- b}{2 a} = \frac{- 0}{2 \times 2}$= 0

Since $2 {x}^{2}$ term is positive, It must be an upward facing curve.

Take a few points on either side of 0. Calculate the y value.

x :y
-3: 24
-2: 14
-1 :8
0: 6
1 :8
2 :14
3 :24

Plot the points. Join them with the help of a smooth curve. graph{2x^2+6 [-58.5, 58.55, -29.25, 29.2]}