# How do you graph y=3/(2x) using asymptotes, intercepts, end behavior?

Nov 29, 2017

here is the graph:

#### Explanation:

To graph y=3/(2x:

Vertical asymptotes occur at the zeroes of the denominator.

$D = 2 x$
$V A = 0$ and there are no holes.

There is a horizontal asymptote because the degree of the numerator is less than the degree of the denominator:

$H A : \mathrm{de} g N > \mathrm{de} g D = 0$

There is no slant asymptote.

Find Behaviour near V.A (generally +/-0.1 away)
the value is not important, you only need to know the sign of the result:

at $x = 0.1$ = $+$ (positive)
at $x = - 0.1$ = $-$ (negative)

so 0.1 will start in quadrant I in the top left corner at $x = 0.1$ and -0.1 will start in quadrant III in the bottom corner at $x = - 0.1$

There are no x intercepts.
There is no y intercept.

Draw your graph with smooth curves.