How do you graph #y = 3 sec(2x)#?

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Answer 1 · 2018-05-06T13:24:27

As below.

#y = A sec (Bx - C) + D " is the standard form of secant function"#

#"Given : " y = 3 sec (2x)#

#"Amplitude is NONE for a secant function"#

#"Period + (2pi) / |B| = (2pi) / 2 = pi#

#"Phase shift " = - C / B = 0#

#Vertical shift " = D = 0#

graph{3 sec (2x) [-10, 10, -5, 5]}