# How do you graph y>=3-x?

Solving linear inequalities in two variable is very easy when you can write is as $y \setminus \ge f \left(x\right)$ (or $y \setminus \le f \left(x\right)$).
In these cases, in fact, the graph of $f \left(x\right)$ represents the points where $y = f \left(x\right)$ holds. To solve $y \setminus \ge f \left(x\right)$ you'll need to consider all the points "above" the graph, and vice versa for $y \setminus \le f \left(x\right)$.
In your case, $f \left(x\right) = 3 - x$, which is a line. A line can be graphed once two of its points are known. You can choose two easy points by setting $x = 0$ (obtaining $y = 3$), and $x = 3$ (obtaining $y = 0$).
So, the points $\left(0 , 3\right)$ and $\left(3 , 0\right)$ belong to the line. Connect them to find the graph of the line, and consider all the points above the line to solve the inequality.