How do you graph #y=4-sin3(x-pi/3)#?

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Answer 1 · 2018-08-03T02:06:57

As below.

Standard form of a sine function is #y = A sin (Bx - C) + D#

Given : #y = - sin (3x - (3pi)/3) + 4#

#A = -1, B = 3, C = pi, D = 4#

#Amplitude = |A| = |-1| = 1#

#"Period " = (2pi) / |B| = (2pi)/3#

#"Phase Shift " = (-C) / B = (-(3pi)/3) / 3 = -pi, color(red)(pi " to the LEFT"#

#"Vertical Shift " = D = 4#

graph{- sin(3x - pi) + 4 [-10, 10, -5, 5]}