# How do you graph #y> -4-x# on the coordinate plane?

##### 2 Answers

See a solution process below:

#### Explanation:

First, solve for two points as an equation instead of an inequality to find the boundary line for the inequality.

**For:**

**For:**

We can now graph the two points on the coordinate plane and draw a line through the points to mark the boundary of the inequality.

graph{(x^2+(y+4)^2-0.125)((x+4)^2+y^2-0.125)(y+x+4)=0 [-20, 20, -10, 10]}

We can now change the boundary line to a dashed line because the inequality operator does not contain an "or equal to" clause. And, we can shade the right side of the line.

graph{(y+x+4) > 0 [-20, 20, -10, 10]}

See below.

#### Explanation:

First graph the line

With line plotted, check a set of coordinates above and below the line to see which satisfy the inequality.

graph{y=-x-1 [-10, 10, -5, 5]}

Above the line:

**TRUE**

Area above the line is the included region. Shade this region.

graph{y > -4-x [-41.1, 41.07, -20.55, 20.55]}