How do you graph #y=4sin(2x-pi/2)#?

Question

8167 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-04-18T13:14:22

Your function is a sine function with amplitude #4# and starting (at #x=0#) with a value of #-4# (#=4sin(-pi/2)#):
enter image source here