How do you graph #y=-5/2x-3# using slope and intercept?

1 Answer
Aug 9, 2017

Answer:

#"see explanation"#

Explanation:

#"the equation of a line in "color(blue)"slope-intercept form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(y=mx+b)color(white)(2/2)|)))#

#"where m represents the slope and b the y-intercept"#

#y=-5/2x-3" is in this form"#

#rArr"slope "=-5/2" and y-intercept "=-3#

#"plot the point "(0,-3)#

#m=-5/2# slopes downwards from left to right 5 units vertically and 2 units horizontally from point to point.

#"from "(0,-3)# move 5 units up and 2 units left to obtain the point
#(-2,2)#

Or move 5 units down and 2 units right to obtain #(2,-8)#

#"plot these points and draw a straight line through them"#
graph{(y+5/2x+3)((x-0)^2+(y+3)^2-0.04)((x+2)^2+(y-2)^2-0.04)((x-2)^2+(y+8)^2-0.04)=0 [-20, 20, -10, 10]}