How do you graph #y=5sqrtx#, compare it to the parent graph and what is the domain and range?

1 Answer
Feb 1, 2018

See details below

Explanation:

We know that #y=5x^2# has the form graph{5x^2 [-5.06, 6.043, -1.09, 4.455]}
We know also that #y=sqrtx# is inverse of #y=x^2#. Hence both graphs are simmetric with respect to #y=x# graph{x [-8.71, 11.29, -2.53, 7.465]}
For those reasons #y=5sqrtx# has the following form graph{5x^0.5 [-23.7, 163.9, -15.86, 77.8]}
Note that the last graph has no trace under x axis
Dom #y=5sqrtx# is #[0,prop)# and Range is also #[0,prop)#