How do you graph # y = abs(4x + 2 ) + 3#?

1 Answer
May 1, 2016

Answer:

#y>=3#. Draw the straight lines #y = 3, y =4x +5 and y = -4x+ 1#.
Sans the parts below the point of intersection (-1/2, 3), the 2nd and 3rd form the graph, for the given equation.

Explanation:

Importantly, #y>=3#.

The given equation is the combined equation for the separate equations

#y =(4x+2)+3 and y= -(4x+2)+3#.. Simplified, these are

#y =4x +5 and y = -4x + 1#

that represent two straight lines meeting at ( -1/2, 3).

Draw the straight lines # y =4x +5 and y = -4x - 1#.

Sans the parts below the common point, the 2nd and 3rd form the
graph, for the given equation.