# How do you graph #y=abs(x)-2#?

##### 1 Answer

The graph looks like this:

graph{y=absx-2 [-10.125, 9.875, -5, 5]}

#### Explanation:

The absolute value function

graph{y=absx [-9.875, 10.125, -3.68, 6.32]}

This is a function you should probably know well for the future. Anyway, in order to plot

I would start graphing this graph by plotting the vertex (the point where the graph has a tight corner). On the original graph it is

graph{x^2+(y+2)^2<=.04 [-9.875, 10.125, -3.68, 6.32]}

Now you need to draw the two rays coming from this point. To do this, graph one point on either side of

#y = abs(-2)-2 = 2 - 2 = 0#

#y= abs2-2 = 2-2 = 0#

So now we know the points

graph{(x^2+(y+2)^2-0.04)((x-2)^2+y^2-0.04)((x+2)^2+y^2-0.04) = 0 [-10.125, 9.875, -5, 5]}

Now all that you have to do is connect these points.

graph{y=absx-2 [-10.125, 9.875, -5, 5]}

*Final Answer*