# How do you graph #y= ln(5 -x^2)#?

##### 1 Answer

Jun 30, 2016

See the explanation and the graph.

#### Explanation:

For real y,

As

So,

#y'=(-2x/(5-x^2) = 0, at x=0. There is no minimum.

Max y = ln 5, at x =0.

Some data for making the graph;

The graph, in its entirety, will look like a collar, with infinite arms

graph{y-ln (5-x^2)=0[-5 5 -10 1.61]}.