How do you graph y=log_4(x+1)?

1 Answer
Nov 23, 2016

Change log base to e and scale y = ln(x+1) by 1/ln4

Explanation:

y=log_4 (x+1)

Remember that: log_b a = ln a/ln b

Hence y=ln(x+1)/ln4

Therefore the graph of y will be the graph of ln(x+1) scaled by 1/ln4

ln(x+1) is defined for x> -1 and has a single zero at x=0

The graph of y is shown below:

graph{ln(x+1)/ln4 [-10, 10, -5, 5]}