# How do you graph #y=log_5(x+1)+1#?

##### 1 Answer

Check the explanation.

#### Explanation:

Assuiming we know the graph of

The first change is a change of the type

so we are adding a constant *inside* the argument of the function. This changes cause a horizontal shift, to the left if

The second change is like

so the argument is unchanged, and we add a constant to the whole expression. These kind of manipulations cause a vertical shift, upwards if

So, in your case, start from

graph{log(x)/log(5) [-3.55, 16.45, -3.92, 6.08]}

Shift everything to the left by

graph{log(x+1)/log(5) [-3.55, 16.45, -3.92, 6.08]}

Shift everything up by

graph{log(x+1)/log(5)+1 [-3.55, 16.45, -3.92, 6.08]}