How do you graph y=log_6(x-1)-5?

1 Answer
Feb 11, 2018

graph{log(x-1)/log(6)-5 [-1.75, 18.25, -9.28, 0.72]}

Explanation:

The first step would be to know how the basic log(x) function looks:
graph{log(x) [-2, 18, -5.56, 4.44]}
Notice two certain coordinate pairs: (1, 0) and (10, 1)

As you may know log(x) = log_10(x)

If we were to graph log_6(x) we would be able to deduce the coordinate pairs (1, 0) and (6, 1)

Now to graph your requested function of log_6(x-1) -5

We simply apply a phase-shift of 1 unit to the right and 5 units down. We know this because of simple transformation concepts concerning functions.

So we get:
graph{log(x-1)/log(6)-5 [-1.75, 18.25, -9.28, 0.72]}